Search over 10,000 free study notes

Here the key is to remember to differentiate with both x and y with respect to x, where the differential of y is dy/dx. Consider the first term, 3x² : This differentiates to 6x. This is done by...

Reduction: loss of oxygen (or gain of electrons)

As 3 ² is equivalent to (-3)² it follows that the square root of 9 must be + or -3.

F=Eq= 5x10^2 x 1.6x10^-19 = 8x10^-17 N

Kinetic energy theory: deltaEc= Fxd =1/2mv^2

thus v= squareroot(2xFxd/m)

v(proton) = squareroot(2x8x10^-17x1x10^-2/9.1x10^-31)=1.3x 10^6 m/s

Depending on the competence level/ preferred learning method of the child I would teach verbs slightly differently. For example, repetition through games, songs, acrostics, association with pictures etc. ...