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Rearrange to make p the subject. C + 5 p = a ( C – p )

C+5p = a (c-p)

C+5p = ac-ap

5p+ap=ac-c

p(5+a) = c(a-1)

p=(c(a-1))/(5+a)

Answered by Santiago M. • Maths tutor

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x is an integer such that ‎1≤x≤9, Prove that 0.(0x)recurring=x/99

r=0.0^.x^.

^{r=0.0x0x0x0x....}

^{100r=x.0x0x0x (1)}

^{10,000r=x0x.0x0x0x (2)}

^{(2) - (1): 9,900r=x00}

Answered by Ellie E. • Maths tutor

12345 Views

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2951 Views

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3118 Views