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A) Acceleration is the rate of change of velocity with respect to time; therefore, in order to calculate it we need to differentiate the given equation of velocity v with respect to time t: a = dv / dt = ...

*Use identity sinxcosx = 1/2sin2x

=5/2sin2x + 5cosx

*then use simple integration gives

=(-5/2 x1/2)cosx + 5sinx + c

= =5/4cosx +5sinx + c

5 + 5√ 2 - √ 8 - √ 16    (Break up all terms in terms of square roots of 2)

5 + 5√ 2 - √ 8 - 4

5 + 5√ 2 - 2 √ 2 - 4 

1 + 3√2

Sinx differentiates to give cosx.

We then multiply this by the differential of "2x."

Which equals 2.

Our answer therefore is "2cos(2x)."

First, we need to draw a diagram, to understand the question more clearly. 
y = x^2 is a common curve, but to sketch y = 4x - x^2, we should factorise it, to find where it inersects...