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Maths
A Level

y = 2t^2, and x = 3t^3 - 2. Find dy/dx in terms of t.

dy/dt = 4t dx/dt = 9t^2dy/dx = dy/dt * dt/dx= 4/(9t)

TM
Answered by Theo M. Maths tutor
5516 Views

If I throw a ball, of mass 2kg, straight up in the air, with velocity 10ms-1, how long until it lands? Assume gravity = 10ms-2

Using SUVAT-s = ut + 1/2 at^2Subbing in... 0 = 2t - 5t^2t = 5/2 = 2.5

TM
Answered by Theo M. Maths tutor
2710 Views

Find the stationary points of the graph x^3 + y^3 = 3xy +35

Differentiate wrt x to get 3x2 + 3y2dy/dx = 3y + 3x dy/dx Rearrange to get dy/dx = (3x2 - 3y)/(3x-3y2). Set dy/dx =0 and infer y=x2. Substitute in fo...

JB
Answered by Joe B. Maths tutor
8906 Views

Differentiate y=ln(x)+5x^2, and give the equation of the tangent at the point x=1

First differentiate the equation, giving you, y'=(1/x)+10x. To get the gradient at this point of the curve, plug in x=1, to get a y' value of 11, and a y value of 5. From there you can plug these three nu...

HM
Answered by Harrison M. Maths tutor
3141 Views

Find the stationary points of y = (x-7)(x-3)^2.

This problem requires the use of the product rule.Let u= x-7 ; by differentiation du/dx = 1. Let v = (x-3)^2 ; by differentiation using the chain rule, dv/dx = 2(x-3)
Product Rule: dy/dx = u*...

SF
Answered by Sam F. Maths tutor
3416 Views

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