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Maths
A Level

How would I solve the equation 25^x = 5^(4x+1)?

You would have to rewrite 25 as 5^2 hence 25^x = (5^2)^x = 5^(2*x).

Then 5^(2x) = 5^(4x+1) and therefore 2x = 4x + 1 hence 2x = -1 hence x = -1 / 2. 

MP
Answered by Marius P. Maths tutor
8468 Views

Prove the identity (4cos(2x))/(1+cos(2x)) = 4-2sec^2(x)

Write down the formulas involving cos2x and select the one which involves only cosine, this is because cosine (or derivations of it) is the only trigonometric function in this question. Substitute the cho...

TN
Answered by Tegan N. Maths tutor
13030 Views

Solve the differential equation: dy/dx = 6x^2 + 4x + 9

dy/dx = 6x2 + 4x + 9

dy = (6x2 + 4x + 9) dx 

integrating gives:

y= (6x3/3) + (4x2/2) + 9x + c

y= 2x3 + 2x2 + 9...

JH
Answered by Jack H. Maths tutor
10919 Views

Where does the quadratic formulae come from?

The general form of a quadratic equation is, ax2 +bx + c = 0. If we divide all terms by a we get, x2 +(b/a)x + c/a = 0. then by completing the square we get (x+(b/2a))+ ...

BO
Answered by Benjamin O. Maths tutor
3751 Views

Can I take a derivative at x=0 for the function f(x) = |x| ?

Just because a function is continuous at a point, that doesn't mean it has a derivative at that point. If a function is differentiable on an interval, then it is continuous on that interval, but the rever...

TD
Answered by Tutor68168 D. Maths tutor
6008 Views

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