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= (2x^2-3)(2x^2-3) -{(2x^2+2)(2x^2+2)}= 4x^4-6x^2-6x^2+9 -(4x^4+4x^2+4x^2+4)= 4x^4-12x^2+9-4x^4-8x^2-4= -20x^2+5= -5(4x^2-1) or 5(-4x^2+1)

For both the two main subjects I intend on teaching in this platform, I highly recommend to my students to focus on the theory as a first step (this could be a definition, some notes, etc). So, by trying ...

This is a inequality question. There are two separate inequalities and the values n can take are the solutions of n that overlap between the 2 inequalities. First inequality: 3n< 12 therefore n <4 ....

If 6x + 2y = 26 then 26 - 6x = 2yy = 13 - 3xSo, using the substitution method.... into 8x + 3y = 328x + 3(13 - 3x) = 328x + 39 - 9x = 32-x + 39 = 3232 + x = 39x = 39 - 32 = 7Sub x = 7 into 6x + 2y = 266(7...

Since x^2-5x+6=0 is a quadratic we need to factorize before solvingAll quadratics fall under this formula ax^2+bx+c=0 so in this case a=1, b=-5 and c=6Drawing the very common ac b table we get: ac|b ...