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Draw out a diagram of a right angled triangle. As the lengths of the sides of the triangle are in the ratio 3:4:5, start off by saying each side is 3cm (a), 4cm (b) and 5cm (c) respectively, with 5cm bein...

We can factorise into (x-3)(x-2)=0 to get x=3 and x=2 as solutions for this equation.

The first task is to multiply out the brackets in the numerator. By doing this, we find that the numerator is equivalent to "12 + 2k". We should now simplify the denominator. We can convert it i...

a) radius = 12/2 = 6cm. Area of a circle = pi x r^2 = 36pi. Area of semi-circle = 36pi / 2 = 18pi cm^2b) Area of full circle = 120. pi x r^2 = 120. r^2 = 120/pi. r = sqr root (120/pi)= 6.18cm

We are going to have to use the cosine rule for this type of question. The cosine rule is a2=b2+c2 - 2bcCosATherefore a2= (6.46.4) + (5.65.6) - (26.45.6)*Cos107.9 If we plug this into ou...