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Maths
GCSE

Show algebraically that (4n-3)^2 - (2n+5)^2 is always a multiple of n-4

First we expand the brackets by squaring each side(4n-3)2 = (4n-3)(4n-3)= 16n2 - 24n + 9(2n+5)2 = (2n+5)(2n+5)= 4n2 + 20n + 25Remember the expression i...

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Answered by Ella B. Maths tutor
3236 Views

Put the following in order of size, smallest first: 8/sqrt3, sqrt6*sqrt2, sqrt48-sqrt27

First part of the question is to recognise that these are surds and we will need to simplify them. Then it is asking to place the values from smallest to highest. In order to simplify the surds we have t...

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Answered by Sandeep S. Maths tutor
3379 Views

solve the Simultaneous equations: y= x+6 and y=2x^23

2x2 = x + 62x2 - x - 6 = 0
[+-1 x-12]2x2 - 4x + 3x - 6 =02x(x-2) 3(x-2) = 0(2x + 3)(x-2) = 0x =2 or -3/2
y = 2 + 6 y = 8
y = -3/2 + 6y = 9/2
(2,8)(-3/2...

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Answered by Lehana D. Maths tutor
3173 Views

Prove that 0.5757... (recurring) = 19/33. Hence, write 0.3575757... (recurring) as a fraction in its lowest terms.

Two parts to the question. Let's focus on part one:Let x = 0.575757... (1)This means that 100x = 57.575757... (2)If you subtract (1) from (2), we get: 99x = 57Divide both sides by 99: x = 57/99Simplify: x...

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Answered by Oliver V. Maths tutor
6656 Views

Find the positive solution to b^2 +5b – 6 =o


(b-1)(b+6)=0b= 1 and -6Positive Solution = 1

Answered by Maths tutor
2788 Views

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