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The question is asking for 'a' to be the subject and therefore our aim is to result in an answer with the form 'a='. The first step is to expand the brackets on the left hand side by multiplying 'a' by 5 ...

Since there is no further factorisation possible we use the quadratic formula x=[-b±√(b²-4ac)]/2a. From the equation in question we have  a=3, b=-7, c=3. Substituting into the quadratic formula...

2x² - x - 6 = 0

This must first be factorised - I use the 'box method' when the reciprocal of x² is >1. This is difficult to explain via writing but it inv...

This equation is asking us to find the value(s) of x that when substituted in place of x in the equation x²-4x+3 the computed value should equal 0. There three potential methods of solving this...

In order to solve the quadratic, we need to factorise it. Consider the coefficient on the x^2, its only factors are 1 and 3 so this tells us that in our factorising we will have something that looks like ...