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When x = 1, y = 10Therefore, p x q^{(1 - 1)} = 10 p x q⁰ = 10 p x 1 = 10, p = 10When x = 6, y = 0.3125 p x q^{(6 - 1)}= 0.3125 10 x q⁵ = 0.3125 q⁵ = 0.0312...

16 = 4² = (2²)² = 2⁴8 = 2³ , therefore 8^2x = 2^3(2x) = 2^6x2⁴ x 2^6x = 2^{4 + 6x}

4(x+13)

To factorise we must think what two numbers add up to 5 but times together to get 6. We know it is two numbers because it is x^(2). If it was x^(3) there could be 3 numbers, ect. We think what goes into 6...

5x + 3 = 455x + 3 - 3 = 45 - 3 (subtract 3 from both sides)5x = 42(5x)/5 = 42/ 5 (divide both sides by 5)x = 8.4 (can either be expressed as a decimal or as fraction)