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We multiply the 2x in the first bracket by everything in the second bracket to give: 2x2-2xWe then multiply the 3 in the first bracket by everything in the second bracket to give: 3x-3Putting 2...
Equation: x2 +4x-5=0 (This is in the form ax2+2bx+c=0)First divide 2b by 2 (4/2=2)Then put this into (x+b)2-(b)2+c=0This gives: (x+2)2-(2)2GJAnswered by George J. • Maths tutor3178 Views
16 = 2482x = (23)2x = 26xTherefore, 16x82x = 24x 26x = 24+6x
Label the two equations as the following: x2 + 2y = 9 y = x + 3 Equation 2 can be substituted into equation 1, giving: x2 + 2( x + 3 ) = 9Expanding the brackets and subtracting ...
You can solve simultaneous equations by either substitution or elimination. Say we have the equations:(1) 8y + 6x = 24 and (2) 2y - x = 6SUBSTITUTION METHODFirst, you need to find x in terms of y (or y in...
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