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Solve (3x +1)/x + (2x-1)/3 = -3, giving x to two decimal places.

(3x+1)/x +(2x-1)/3 = (2x2 + 8x + 3)/3x by cross multiplying.

So equation becomes 2x2+ 8x + 3 = -9x by multiplying both sides by 3x. Adding 9x to both sides gives 2x2

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Answered by Jorge A. Maths tutor
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