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There are a few ways of solving these simultaneous equations, but most of them involve substitution. Perhaps the most intuitive substitution to make is the second equation (y=3x+5) into the first one (xy=...
Assume we have the function:y = x ( x2 + 8x - 9)This function is known as a cubic function as when multiplying out the brackets, the highest function of x would be x3.Not...
In order to do this we must follow the standard procedure for a proof by induction which is to first check a base case:Let n = 1, then the sum can be written as 12 = 1/6(1+1)(2+1) = 1 as requir...
From first equation: 3xy = 1 => x = 1/(3y)Substitute expression for x into second equation: y = 12x + 3 => y = 12(1/3y) + 3 = 4/y +3Multiply through by y: y2 = 4 + 3y => y2HMAnswered by Hallam M. • Further Mathematics tutor2321 Views
zy=28 so y=28/z13=2z-3y13= 2z - (28 x 3)/z13=2z-84/zmultiply each side by z to give 13z = 2z2-84rearange for a quadratic2z2-13z-84=0solve by factorising(2z+8)(z-21/2)z= -4 0r 21/2sub...
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