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Maths
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A straight line goes through (0,1), (2,5) and (4,9). The equation of the straight line is y=2x+1. Is the point (7,12) on this straight line?

  • First we'll figure out what the numbers in the co-ordinates mean. On the point (7,12) x= 7 and y=12. - The equation of the line is in the form of y=mx + c so for the point to be on the line, the y v...
HC
Answered by Harriet C. Maths tutor
8944 Views

How do you solve a quadratic equation? I always forget how to do that!

x2+4x+3=0 The first step is to factorise. To do this you need to find a pair of factors of 3 that add together to make 4. I recommend listing the factors of 3 to start with. Don't forget the ne...

HD
Answered by Hannah D. Maths tutor
3163 Views

Solve: x^8-17x^4+16

You should treat the question as you would a normal quadratic and complete the square. First you should look at the factors of 16 and see which pair would result in the -17x; you can see that it would be ...

JG
Answered by Jessica G. Maths tutor
11978 Views

3(a+4)=ac+5f. Rearrange to make a the subject.

3(a+4)=ac+5f

3a+12=ac+5f

3a-ac=5f-12

a(3-c)=5f-12

a= (5f-12)/(3-c)

RR
Answered by Rumana R. Maths tutor
4296 Views

1. The curve C has equation y = 3x^4 – 8x^3 – 3 (a) Find (i) d d y x (ii) d d 2 y x 2 (3) (b) Verify that C has a stationary point when x = 2 (2) (c) Determine the nature of this stationary point, giving a reason for your answer.

To differentiate use formula.

multiply factor by power then minus one from power (where x is invloved)

dy/dx = 12x^3 - 24x^2

d^2y/dx^2 = 36x^2 - 48x (this is just a further differenti...

EI
Answered by Elysa I. Maths tutor
15137 Views

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