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dx/dt=-5x/2 t>=0 when x=60 t=0

dx/dt=-5x/2 Int(x, dx)=Int(-5/2, dt) ln(x)=-5t/2+c x=60 when t=0 ln(60)=c ln(x)=ln(60)-5t/2 x=eln(60)-5t/2 x=60/e5t/2

FD
Answered by Felix D. • Maths tutor
4811 Views

Solve the simultaneous equations x^2 + y^2 = 9 and y = 3x + 3

y2 = (3x + 3)2 = 9x2 + 18x + 9

x2 + 9x2 + 18x + 9 = 9

10x2 + 18x = 0 (root a: x = 0)

5x + 9 = 0 (root b: x = -1.8)

AR
Answered by Alistair R. • Maths tutor
4099 Views

How would you increase 400 by 7%

First, we'd want to find out what 1% of 400 is. If 400 is the total number, that would make 400 the whole 100%. In order to find out 1% we'd want to divide the number by 100 which is 4. Now that we know 1...

TT
Answered by Tharani T. • Maths tutor
12046 Views

Given that sin(x)^2 + cos(x)^2 = 1, show that sec(x)^2 - tan(x)^2 = 1 (2 marks). Hence solve for x: tan(x)^2 + cos(x) = 1, x ≠ (2n + 1)π and -2π < x =< 2π(3 marks)

sin(x)2 + cos(x)2 = 1

Dividing by cos(x)2 gives:

tan(x)2 + 1 = sec(x)2 

Which rearranges as:

sec(x)2 - tan(x)<...

AR
Answered by Alistair R. • Maths tutor
3923 Views

Find the exact length of side A in the triangle and give you answer in the simplest form. (It is a right angled triangle. Side C is (6+√(3)) and side B is (3 + 2√(3)).

a2 + b2 = c2    (Pythagoras' Theorem) 

a2 + (3 + 2√(3))(3 + 2√(3)) = (6 + √(3))(6 + √(3))    (Expanding brackets)

a2 + 9 + 6√(3) + 6√(3...

RA
Answered by Rebecca A. • Maths tutor
3977 Views

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