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Solve x^2+8x-5 = 0 by completing the square.

x² + 8x = (x + 4)² - 16, so x² + 8x - 5 = (x + 4)² - 16 - 5 = (x + 4)² - 21, so then (x + 4)²- 21 = 0 (x + 4)²= 21 -----> ...

Answered by Shadab J. • Maths tutor

11905 Views

Find the equation for the tangent to the curve y^3 + x^3 + 3x^2 + 2y + 8 = 0 at the point (2,1)

As the tangent has the same gradient as the curve at the particular point, we need to find the gradient of the curve. To find the gradient we need to differentiate. Due to there being two variables in thi...

Answered by Aphishek E. • Maths tutor

4285 Views

Find an equation of the straight line that is perpendicular to the straight line x + 3y = 7 and that passes through the point (4,9).

y = 3x - 3

Answered by Vikesh P. • Maths tutor

3405 Views

solve: x^2= 4(x-3)^2

x^2= 4(x^2 - 6x + 9)

x^2= 4x^2- 24x + 36

3x^2 - 24x + 36= 0

(x-2)(x-6)=0

x= 2 or x=6

Answered by Ghazn K. • Maths tutor

3370 Views

How do I find the nature of a stationary point

Firstly, note that a stationary point can either be a local maximum, local minimum or point of inflexion. Now suppose you have a differentiable function (a graph which has a unique gradient/derivative at ...

Answered by Curtis C. • Maths tutor

6165 Views