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Solving simultaneous equations by elimination; firstly you would multiply the first equation by 4 to get another equation which we will name (3), and multiply the second equation by 3 to get another equat...

We need to find numbers that multiply together to give -15. This could be -1 and 15, 1 and -15, -3 and 5, 3 and -5. The numbers we need must add up to -2 as well (from -2x term). Therefore our set must be...

(x-4x³) = x(1-4x²)  Just taking a factor of x out of both terms Within the inner bracket we have a difference of two squares. 1²=1 and (2x)²=4x² ther...

x=((y+2)/3)^1/2

First we will need to factorise the equation.

Start with the 3x^2 term and notice 3 is prime so must have 3x and x terms.

(3x - 9) (x + 1) or  (3x + 3) (x - 3)

Setting the brackets to...