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0= (x + 4)(x + 1)

x= - 4

x= - 1

lnx differentiates to 1/x

4x^2 differentiates to 8x

3e^4x differentiates to 12e^4x

therefore the answer is: 1/x + 8x + 12e^4x

(4x-5)^2-5x(3x-8)

(16x^2-40x+25)-(15x^2-40x)

16x^2-15x^2-40x+40x+25

x^2+25

if x = positive, x^2 will be positive.

if x = negative, x^2 will be positive.

x^2 is po...

x=0.81

A simple implementation of Pythagoras' Theorem a²+b²=h², and as in the question c is the hypotenuse, a²+b²=c². (Side Note - in exams, the ...