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The curve y = 2x^3 - ax^2 + 8x + 2 passes through the point B where x=4. Given that B is a stationary point of the curve, find the value of the constant a.

As B is a stationary point, the value of dy/dx at this point must be equal to 0. Differentiating y gives this to be dy/dx = 6x²-2ax+8. At point B, <...

Answered by Evan H. • Maths tutor

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How would one multiply out brackets?

If asked to multiply out a set of brackets, one must remember to multiply each term in a set of brackets by every term in the other set of brackets. For example, (x+2)(x-4) = x²+2x-4x-8 = x

Answered by Alden R. • Maths tutor

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find the inverse function of the following: f(x) = 3x-5

in an inverse function, simply put the x and y are inversed: meaning x becomes y, and y becomes x

f(x): y=3x-5

f-1(x): x=3y-5 <=> x+5=3y <=> (x+5)/3 = y <=>

Answered by Olivia T. • Maths tutor

4950 Views

How do you integrate x* (exp(x))??

The easiest method to use in this incidence is integratation by parts.

So let u=x and dv/dx=exp(x). Therefore du/dx=1 and v=exp(x).

Then we use the formula where integral(udu/dx)=uv...

Answered by Harmony J. • Maths tutor

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Differentiate y=x^3*(x^2+1)

As this is a product of two functions it is necessary to use the product rule for differentiation. Therefore one of the functions must labeled v and the other u. i.e. u=x^3 and v=(x^2+1). It is then neces...

Answered by Bevan J. • Maths tutor

3682 Views