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We shall differentiate each term in the equation with respect to x.
dy/dx (x2) = 2x
dy/dx (2y2) = 4y dy/dx
dy/dx (3x) = 3
So we now have the equation 2x +...
We are going to use the F.O.I.L Method for this expansion,
FIRST
2x*x = 2x2
OUTSIDE
2x*3 = 6x
INSIDE
-4x*x = -4x
...
Substitute in each letter for the appropriate number that it equals. Q = 36 / (3 x (4--2)) Q = 36 / (3x(4+2)) Q = 36 / (3x6) Q = 36 /18 Q = 2
Volume of cone= 1/3Pihr^2 r=2.25 V=1/3Pi102.25^2=53.01 cm^3=5.301x10&-5 m^3 Mass=density*volume Mass=(5.301x10^-5)1095= 0.05805 kg Mass of 5= 0.058055=0.290 kg
Multiply everything through by ex and rearrange so it equals zero you now have e2x -ex-6=0 It is now similar to a quadratic equation, make the dummy substitu...
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