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dx=du/6 => (u-5)/6=x So the integral is now (2((u-5)/6)-3)(u^1/2) du/6 Which through simplifying becomes (1/36)(2u-28)(u^1/2)du = (1/36)(2u^3/2 -28u^1/2)du After integrating becomes (1/36)(4(u^5/2)/5 -...

Step 1: (5t+3)/4 = 1 Step 2: (5t+3)= 1 x 4 Step 3: 5t + 3 = 4 Step 4: 5t = 4 - 3 Step 5: 5t = 1 Answer: t = 1/5 

The best method to revise is through solving past questions and timed exam papers. As long as you have your notes and understand all the basic principles, then you just need to practice in order to avoid ...

Let $ denote the integral symbol, as I am limited here by my keyboard.

Recall the formula for integration by parts:

$ u.(dv/dx) dx = uv - $ u(dv/dx) dx

So to find $^pi_0...

Convert all fractions denominator into 12

3/12 , 8/12, 6/12,  4/12

Hence in order

1/4, 2/6, 1/2, 2/3