Search over 10,000 free study notes

First, clearly write the two equations above one another, and label them (1) and (2). Rearrange the linear equation (the one with no squared variables) to make y the subject of the equation. You should ge...

To compliment Mathematics, Further Mathematics would be an ideal subject to take. It is not essential, however the additional practice would benefit your understanding of Mathematics, easing you into even...

First we must find the y coordinate of the point P: We know the x-coordinate is x1=1 so the y coordinate must satisfy the equation y1=f(1) which gives y1=-7. So we now know P is at (1,-7).

We now n...

From the given quadratic, we have a=1, b=-1, and c=-6. We substitute these values into the quadratic formula, x=-b+-sqrt(b^2-4ac)/2a, giving us x=-1+-sqrt(-1^2-41-6)/2*1. This simplifies to x=1+-...

We know that 3 x 16 = 48 This is equivalent to saying 3 x 4^2 = 48 Therefore the square root of 48 can be written as square root of (4^2 x 3) = 4 x square root 3