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You would use the quadratic formula when trying to find the value of a variable such as x in a quadratic equation but it can not be successfully factorised with whole numbers. Treating the the equatio...
let y=2x {take natural logs of both sides}
cos2x= 2cos^2x - 1
2cos^2x - 1 - 5cosx = 2
Let cosx = y
2y^2 - 5y - 3 = 0
(2y + 1)(y + 3) = 0
y = -1/2 or -3
cosx = -1/2 or -3
x = 120 degrees
= 1 + 3x1/3 + (1/3-2/3)(3x)^2 + (1/3*-2/3*-5/3)(3x)^3
= 1 + x - 2x^2 + 10x^3
Please note: knowledge of the SUVAT equations, friction and trigonometry is required for this thread.
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