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a) 1/6b) £20c) £20+£10+(0.1*£30)= £33

b)243*8=24

7xy+3y2=10x 3y2=10-7xy 3y2=x(10-7y) 3y2/10-7y=x

solve 64^2/3 ... note X^2/3 = X^{2 x 1/3} therefore 64^2/3= (64²)^1/3= (4096) ^1/3= 16

Using quotient rule, let u = 2x+12 and v = 1-x. Then we differentiate u and v separately, so u' = 2 and v' = -1. The formula for the quotient rule is: (vu' - uv')/v^2. Plugging in our values into this equ...