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There are 10 boys and 20 girls in a class. The class has a test. The mean mark for all the class is 60. The mean mark for the girls is 54. Work out the mean mark or the boys.

Total mark for whole class is 3060= 1800Total mark for girls is 2054= 1080
Therefore subtract smaller from larger to get total mark for boys, and divide that number by 10 to yield 72.

RM
Answered by Raphael M. Maths tutor
3070 Views

The equation of line 1 is y=3x-2 and the equation of line 2 is 3y-9x+5=0. Show the two lines are parallel.

The two lines are parallel if they have the same gradient, so for a line in the form y=mx+c, m of the two lines must be the same.Line 1 is already in this form so we need to rearrange line 2 to be in this...

ES
Answered by Emma S. Maths tutor
2978 Views

y = x^2 − 2*x − 24*sqrt(x) - i) find dy/dx ii) find d^2y/dx^2

Solved by differentiation with respect to x,i) dy/dx = 2x - 2 - 12x^(-1/2)ii) d^2y/dx^2 = 2 + 6*x^(-3/2)

DG
Answered by Duncan G. Maths tutor
5477 Views

Complete the indefinite integral of 3x^2 + 4x -2/(x^2)

for each of the terms in x, the power to which x is raised increases by 1, and then each term is divided by the new power. A constant of integration is introduced because we were not asked to integrate be...

EC
Answered by Ed C. Maths tutor
3782 Views

Find the equation of a straight line that passes through the points (2,7) and (5,3)

Since we're told the line is straight, the equation of the line will be of the form y = mx + c.The gradient of the line, m, is the change in y divided by the change in x ; m = (3-7)/(5-2) = - 4/3.Therefor...

JN
Answered by Joshua N. Maths tutor
3340 Views

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