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The curve C has an equation y = sin(2x)cos(x)^2. Find dy/dx. Find normal to curve at x = pi/3 rad, giving answer in exact form.

Student should use a combination of trigonometric identities, product rule and chain rule to find dy/dx.This can be done by applying product rule, obtainingdy/dx = sin(2x). d[cos(x)^2]/dx + cos(x)^2. d[si...

Answered by Sunchi C. • Maths tutor

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Solve the equation 3 sin^2 theta = 4 cos theta − 1 for 0 ≤ theta ≤ 360

I would convert the sin squared theta into a cos squared theta using identity that sin sq + cos sq = 1This would then give me a quadratic equation which I would substitute X = cos thetaThen I would solve ...

Answered by Mario L. • Maths tutor

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Simplify 125^-2/3

125^-2/3= 1/125^2/3=1/(cube root(125))^2=1/5^2=1/25

Answered by Amy W. • Maths tutor

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The circle C has centre (3, 1) and passes through the point P(8, 3). (a) Find an equation for C. (b) Find an equation for the tangent to C at P, giving your answer in the form ax + by + c = 0 , where a, b and c are integers.

A)1) Draw a diagram of the circle displaying the centre and perimeter points along with their respective co-ordinates.2) Write down the equation for a circle labelling the centre and perimeter points. 3) ...

Answered by Patrick V. • Maths tutor

8214 Views

A prism with a triangular cross section has volume 120cm^3. The base of the triangular face has length 6cm. The width of the prism is 10cm. The height of the triangular face is h. Find h.

Cross sectional area: half base x height = (6/2)h = 3h , Volume of prism: Cross sectional area x width, this gives: 3h10 = 120, rearrange: 3h = 12, Find h: h = 4cm.

Answered by Jake V. • Maths tutor

4692 Views