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f(x)=(2x+1)/(x-1) with domain x>3. (a)Find the inverse of f(x). (b)Find the range of f(x). (c) g(x)=x+5 for all x. Find the value of x such that fg(x)=3.

(a) Let y=f(x). Then y = (2x+1)/(x-1). Rearrange the equation to get x in terms of y to obtain the inverse function. This gives x=(1+y)/(y-2). So the inverse of f is f-1(x)=(1+x)/(x-2)<...

LA
Answered by Lutfha A. Maths tutor
5787 Views

Solve this pair of simultaneous equations: 3x + 2y = 4 and 2x + y = 3

2x + y = 3   therefore  y = 3 - 2x

Substitute y = 3 - 2x in to the first equation:

3x + 2(3 - 2x) = 4

3x + 6 - 4x = 4

-x = -2   therefore x = 2

Substitute x = 2 in to ei...

TC
Answered by Tim C. Maths tutor
6627 Views

Solve x² - 3x - 2 = 0

To complete the square for the equation ax² + bx + c = 0 there are three steps.. 1. In order to complete the square, we need to take the first two parts of the quadtratic equation, and put them in the for...

NM
Answered by Natalia M. Maths tutor
11855 Views

Use the equation 2(x+4) + 6(x-1) = 14, to find x.

Firstly, you need to get rid of any brackets. You do this by expanding them. This becomes 2x + 8 + 6x - 6 = 14.

The next step is to get all the x's on one side, and all the numbers on the other. Yo...

UR
Answered by Ursula R. Maths tutor
3680 Views

Find dy/dx for y = x^3*e^x*cos(x)

In this problem, we see that y is a product of 3 functions of x. That means that in order to find dy/dx we need to use the product rule. The product rule tells us that in this case we should differentiate...

LN
Answered by Lyudmil N. Maths tutor
10495 Views

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