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x₁ = (-b + (b² - 4ac)^1/2)/2a and x₂ = (-b - (b² - 4ac)^1/2)/2a. So with the values a = 1, b = 3 and c = 2: x₁ = (-3 + (3^{2 <...}

x²+2x+1=0, (x+1)(x+1)=0, (x+1)²=0. So x=-1

The differential of a function is defined by the expression: dy/dx = Lim(dx->0) of (f(x+dx)-f(x))/dx. For functions only involving powers of x, the differentioal can easily be calculated by timesing by...

Let eqn. 1 be: 3x + 2y - 1 = 0  & Let eqn. 2 be: 4x - 6y -10 = 0

Multiply eqn. 1 by a factor of 3, and add the two eqautions together. (This eliminates y from the equation)

This gives: 9...