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7x+y=1 (1) -> y= 2x2 - 3 (3)
7x + 2x2 -3-1=0 -> (2x-1)(x+4)=0 so 2x-1=0 so 2x=1 so x=0.5 and x+4=0 so x=-4
7(0.5)+y=1 so y=1-3.5 so y=-2.5 and 7(-4) +y=1 so -2...
When you multiply two numbers that are the same with different exponents, the number can remain the same and the exponents are added. That is an exponents rule. This means that the answer is p^7
Layout the problem in a more recognisable form such as (3 - sqrt(5))(3 - sqrt(5)). Notice that this looks a lot like a factorised quadratic equation, where <...
A fraction is simply a different way to write a division sum. I.e a \divide b = a/b.
This also applies if the two numbers we're dividing are fractions themselves:
a/b \divide c/d = (a/b) / (...
(x + 7)*(x - 7)
Notice difference of two squares. Very important to learn square numbers, primes and multiples and be able to notice them.
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