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2kx + 6ky + 4kz

=2k (x + 3y + 2z)

Since 1/5 of the class is absent, this must mean that 4/5 of the class is present. We are told that 24 pupils are present, so 4/5 of the class must equal 24 pupils. Now we need to find out how many pupils...

6a + b = 16    Equation 1
5a - 2b = 19    Equation 2

Scale up one equation so both equations have same coeffient of one variable ie 2 times Equ 1

12a + 2b = 32
5a - 2b = 19

By factorising the expression, (x-5)(x-4)=0. This means that either (x-5)=0 or (x-4)=0. By solving these equations we can work out the solutions to be x=4,5.

First thing to do is to find the stationary point of the curve. This is done by differentiating the function and then equating to zero, as the gradient of the stationary point is zero. Setting dy/dx to ze...