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How do I find the expression for the nth term in a series of numbers?

First write down the series of numbers e.g.  8,  12,  16,  20.

Calculate the difference between each term in the series 12-8 = 4, 16-12 = 4,  20-16 = 4 This shows that the expression will begin wit...

MB
Answered by Megan B. • Maths tutor
17977 Views

Differentiate with respect to x: y=(6x^2-1)/2sqrt(x)

1st Step: Must separate the fractions and simplify:

y= (6x2-1)/2sqrt(x)= 6x2/(2x1/2) - 1/(2x1/2) 

Cancel 6 with 2 and x

ES
Answered by Elena S. • Maths tutor
8425 Views

Factorise and solve x^2 - 8x + 15 = 0.

Whenever faced with a quadratic equation in the form of AX^2 + BX + C = 0, the first thing you do is factorise it, which will look something like this: (X )(X ) = 0.You can see from this that when you mul...

ZN
Answered by Zarmala N. • Maths tutor
3011 Views

i) It is given that f(x)=(-5-33x)/((1+x)(1+5x)), express f(x) in the form A/(1+x) + B/(1+5x) where A,B are integers. ii) hence express the integral of f(x) between x=3 and x=0 in the form (p/q)ln4 where p,q are integers.

i) -7/(1+x) + 2/(1+5x) ii) (-31/5)ln4

DT
Answered by Damon T. • Maths tutor
3913 Views

find the integral of ((3x-2)/(6x^2-8x+3)) with respect to x between x=2 and x=1. (hint use substitution u=denominator)

(ln11)/4

DT
Answered by Damon T. • Maths tutor
3984 Views

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