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Find the equation for the tangent to the curve y^3 + x^3 + 3x^2 + 2y + 8 = 0 at the point (2,1)

As the tangent has the same gradient as the curve at the particular point, we need to find the gradient of the curve. To find the gradient we need to differentiate. Due to there being two variables in thi...

AE
Answered by Aphishek E. Maths tutor
4351 Views

Find an equation of the straight line that is perpendicular to the straight line x + 3y = 7 and that passes through the point (4,9).

y = 3x - 3

VP
Answered by Vikesh P. Maths tutor
3453 Views

solve: x^2= 4(x-3)^2

x^2= 4(x^2 - 6x + 9)

x^2= 4x^2- 24x + 36

3x^2 - 24x + 36= 0

(x-2)(x-6)=0

x= 2 or x=6

GK
Answered by Ghazn K. Maths tutor
3403 Views

How do I find the nature of a stationary point

Firstly, note that a stationary point can either be a local maximum, local minimum or point of inflexion. Now suppose you have a differentiable function (a graph which has a unique gradient/derivative at ...

CC
Answered by Curtis C. Maths tutor
6237 Views

Solve the following equation: x^2 - 11x + 18 = 0

Use the factorisation method.

Step 1: Rewrite (x + __ )(x + __ ) = 0

Step 2: We need to fill in the blanks. The numbers we require are -2 and -9.

Step 3: We need the values of x, so t...

TD
Answered by Tutor54985 D. Maths tutor
17697 Views

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