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A stationary point on a curve is when the differential of the equation of the curve = 0. In other words when dy/dx = 0Take the equation in the question: y = 20x - x² - 2x³A simple ru...

a = 4b + 5(c - b) - question8 = (4*7) + 5(c - 7) - insert values given in question8 = 28 + 5c -35 - multiply and expand brackets8 - 28 + 35 = 5c - take away 28 from the left and right-hand side of the equ...

Note the formula: y - y₁ = m(x - x₁)x, y, x_1, y₁ refer to the values of your given coordinates. 'm' symbolises the gradient of the line you are asked to findRe...

First put the equation into the correct form by setting it to 0:18x^2-3x-6=0Look for the common factor in the equation and take it out:3(6x^2-x-2)Using the grid method (which I would show on whiteboard) f...

Firstly, expand out the (2x+3y)^2 as (2x+3y)(2x+3y).Multiplying each term in the first bracket with each term from the second bracket gives 4x^2+6xy+6xy+9y^2 which simplifies to 4x^2+12xy+9y^2 by adding t...