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Find the coordinates of the turning points of the curve y = 4/3 x^3 + 3x^2-4x+1

First differentiating by the rule that xn differentiates to nxn-1 we have that dy/dx = 4x2+6x-4.
At the turning points of a curve the differential is equal to 0 so w...

TE
Answered by Theo E. Maths tutor
9370 Views

Solve the linear simultaneous equations: 3x + 5y = 45, 2x - 9y = -7

x = 10, y = 3. From the second equation, we have x = (9y - 7)/2. Substituting this expression for x into the first equation gives 3(9y - 7)/2 + 5y = 45. 3(9y - 7) + 10y = 90. 27y - 21 + 10y = 90. 37y = 11...

CW
Answered by Cameron W. Maths tutor
3991 Views

integrate xcosx

use integration by parts

SB
Answered by Sebastian B. Maths tutor
3850 Views

Find the minimum and maximum points of the graph y = x^3 - 4x^2 + 4x +3 in the range 0<=x <= 5.

First, use the standard method of setting the derivative to be equal to 0 to find the stationary points. This yields the equation 3x^2 - 8x + 4 = 0 and so the stationary points are at x = 2/3 and 2 respec...

GM
Answered by Guy M. Maths tutor
6188 Views

A curve has equation x = (y+5)ln(2y-7); (i) Find dx/dy in terms of y; (ii) Find the gradient of the curve where it crosses the y-axis.

(i) To find the derivative we will use the product rule. Let u = y+5 and v=ln(2y-7). Then dx/dy = du/dyv + udv/dy = ln(2y-7) + (y+5)*2/2y-7 (used the chain rule in 2nd term - can explain this on ...

SP
Answered by Szymon P. Maths tutor
11619 Views

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