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We can think of the constant term in a function in terms of x, for example in x^2 + 3x + 2 as 2 being multiplied by x^0. Anything to the power of 0 is equal to one, so in our example we would have 2 * x^ ...

With quadratic equations, there are two ways in which to answer
Firstly (and most simply), look for two numbers that multiply to make c and add up to make b in the equation y = ax² + bx +...

We can break this down into steps, going deeper each time. First we might just say: well, since integration is fundamentally the inverse process of differentiation and we know that the derivative of ln(x)...

Let's have a look at a pair of brackets: (a+b)(c+d)To expand these brackets each value in one bracket must be multiplied by all values in the other bracket separately then added together. So we have: ac+a...

Because if we simply expand (x+y)² we'd get x²+y²+2xy which shows that there's an extra term which is 2xy. another practical way to check your work and see why LHS ≠ RHS i...