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Find dy/dx when y = x(4x + 1)^1/2
Here we can use the product rule where dy/dx = v du/dx + u dv/dx.We let u = x and v = (4x + 1)1/2 which means we get du/dx = 1 and by using the chain rule we get dv/dx = 1/2(4x + 1)-1/2
Here we can use the product rule where dy/dx = v du/dx + u dv/dx.We let u = x and v = (4x + 1)1/2 which means we get du/dx = 1 and by using the chain rule we get dv/dx = 1/2(4x + 1)-1/2
