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Stationary points of an equation are found where the gradient of the tangent at this point equals zero. A diagram can illustrate this. To find them differentiate the given equation (which gives the gradie...

In order to tackle this equation, we have to keep in mind that whatever we do to one side of the equation we have to do to the other. Our aim is going to be to get all of the x's together on one side of t...

This question teaches the importance of drawing diagrams to figure out what a question is asking, as well as deeply testing how well the student understands trigonometry and equation rearrangement, combin...

(1) Find the gradient using differentiation (2) If the gradient at (x₁,y₁) is m,y - y₁ = m(x - x₁)
(1) We differentiate the given equation:dy/dx = 2x + 3 <...

The total number of 'parts' in this ratio is 5+3+2 = 10.

So, to work out how much of the total corresponds to 1 part, we need to divide the t...