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Binomially expand the equation (2+kx)^-3

(2+kx)-3 = (2-3)(1+kx/2)-3 = (2-3)(1+(-3)(kx/2) + [(-3)(-4)]/2! (kx/2)2 + [(-3)(-4)(-5)]/3! (kx/2)3 +... )
= 1⁄8 [1 -(3kx/...

CH
Answered by Christopher H. Maths tutor
9729 Views

Solve the simultaneous equations: 2x + y = 18, x - y =6.

There are 2 different ways to approach solving simultaneous equations: 1) making x or y the subject of one of the equations.2) addition or subtraction method.In this section, I will explain the first meth...

JG
Answered by Jamini G. Maths tutor
17558 Views

Express 112 as a product of it's prime factors.

The easiest way to approach this problem is using a break down tree from the number at the top of the page. Firstly, you can divide 112 by 2 to get 56. Circle the number 2 as this is prime and can no long...

AB
Answered by AIDAN B. Maths tutor
13575 Views

x^2-5x-50=0. Solve for the positive value of x

recognise this equation has the form ax^2 + bx + c =0. An equation with this form is a quadratic. Recognise in a quadratic equation there will be 2 values of x that will equal 0. These 2 values wil...

EF
Answered by Ellis F. Maths tutor
3330 Views

What is the Highest Common Factor of 8 and 24

You would first want to draw out a tree diagram (example given by whiteboard) and divide the number given e.g. 8 in the question by prime numbers e.g. 8 can be split into two branches 2 and 4. 2 is a prim...

FR
Answered by Faisal R. Maths tutor
4747 Views

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