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Expand the brackets: (x-3)(x+4)

First Multiply x by (x +4) Next multiply -3 by(x+4) Then simplify the sum : x2+4x-3x-12 Hence the answer is : x2+x-12

AN
Answered by Anthony N. Maths tutor
3147 Views

1. Find the value of the missing edge to 2 decimal places 2. Find the angle θ to 2 decimal places

The triangle is a right angled triangle with hypotaneuse y, and sides are 7 and 10. The angle θ is between the hypotaneuse and the side of length 10 (I do have a diagram) For question 1: Using Pythagoras’...

AC
Answered by Amelia C. Maths tutor
4168 Views

Let y be a function of x such that y=x^3 + (3/2)x^2-6x and y = f(x) . Find the coordinates of the stationary points .

y = x3 + 1.5x-6x Hence, dy/dx = 3x2 + 3x - 6 Solve to find x when dy/dx = 0 as gradient is zero at stationary points Substitute the vaules for x back into y to find y co...

MC
Answered by Michael C. Maths tutor
3549 Views

Two forces P and Q act on a particle. The force P has magnitude 7 N and acts due north. The resultant of P and Q is a force of magnitude 10 N acting in a direction with bearing 120°. Find the magnitude of Q and the bearing of Q.

There are 2 methods to solving this- the visual method and the kinesthetic method. Here I will use the visual one. We start by creating a vector triangle. We are going to use R = P + Q, where R is the res...

YP
Answered by Yaasir P. Maths tutor
10487 Views

A particle is moving in the with acceleration (2t - 3) ms^-2 and initial velocity 2ms^-1. Find the distance travelled when the velocity has reached 12ms^-1.

(1.) Integrate the expression for acceleration to find an expression for velocity: Velocity v = t^2 - 3t + c        When t = 0, velocity = 2. Substituting in to find constant c, 2 = 0 + 0  + c therefore c...

RF
Answered by Richard F. Maths tutor
5879 Views

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