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if y=3x^2 + x -4 

then 

dy/dx = 6x + 1

setting this equal to zero gives

6x + 1 = 0

so then

x = -1/6

putting this x value back into the original equation gi...

This would be a question that would test the students understanding of Pythagoras' Theorem. When teaching this before I have often found that students are scared of thee questions because of the name, so ...

First find the difference between the numbers. Do this by subtracting the first number from the second number...

18

-7

11

Double check this to see if this runs true for ...

a) y = 9 -6x^2 - 12x^4 

dy/dx = -12x - 48x^3 

b) At stationary points dy/dx = 0. 

-12x - 48x^3 = 0 

48x^3 + 12x = 0 

4x^3 + x = 0

x (4x^2 + 1) = 0 

Either ...

1. We the answer in question in the form A(1+B)^0.5 and we can do that by factorising out the 5. This gives 5^0.5(1+0.4x)^0.5. 2. Identify the formula we are going to use ...