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differentiate x^2 + y^3 + xy respect to x

2x + 3y2 * dy/dx + x * dy/dx +y 

XJ
Answered by Xianming J. • Maths tutor
3030 Views

dx/dt=-5x/2 t>=0 when x=60 t=0

dx/dt=-5x/2 Int(x, dx)=Int(-5/2, dt) ln(x)=-5t/2+c x=60 when t=0 ln(60)=c ln(x)=ln(60)-5t/2 x=eln(60)-5t/2 x=60/e5t/2

FD
Answered by Felix D. • Maths tutor
4417 Views

Solve the simultaneous equations x^2 + y^2 = 9 and y = 3x + 3

y2 = (3x + 3)2 = 9x2 + 18x + 9

x2 + 9x2 + 18x + 9 = 9

10x2 + 18x = 0 (root a: x = 0)

5x + 9 = 0 (root b: x = -1.8)

AR
Answered by Alistair R. • Maths tutor
3643 Views

How would you increase 400 by 7%

First, we'd want to find out what 1% of 400 is. If 400 is the total number, that would make 400 the whole 100%. In order to find out 1% we'd want to divide the number by 100 which is 4. Now that we know 1...

TT
Answered by Tharani T. • Maths tutor
10384 Views

Given that sin(x)^2 + cos(x)^2 = 1, show that sec(x)^2 - tan(x)^2 = 1 (2 marks). Hence solve for x: tan(x)^2 + cos(x) = 1, x ≠ (2n + 1)π and -2π < x =< 2π(3 marks)

sin(x)2 + cos(x)2 = 1

Dividing by cos(x)2 gives:

tan(x)2 + 1 = sec(x)2 

Which rearranges as:

sec(x)2 - tan(x)<...

AR
Answered by Alistair R. • Maths tutor
3312 Views

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