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Solve the simultaneous equations: x^2 + y^2 = 29 and y - x = 3

To solve these equations we need to eliminate one of the variables, so make y the subject of the second equation: y = x + 3. Now y can be substituted into the first equation: x^2 + (x+3)^2 = 29. Expanding...

TG
Answered by Trisha G. Maths tutor
4482 Views

Solve 3(x-2) = 21

To begin, understanding the basica concept of algebra and multiplication using brackets needs to be covered as I have met quite a few children who have been used to these equations but are still unsure ab...

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Answered by Nicole F. Maths tutor
3954 Views

Expand and simplify (6x - 2y)(3x - 7y)

Expand brackets: 18x^2 - 42xy - 6xy + 14y^2 Simplify: 18x^2 - 48xy + 14y^2

3 marks

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Answered by Beth W. Maths tutor
6423 Views

How many thirds are there in 9?

A third is exactly how it sounds: 1 piece out of 3 pieces of one number. If you imagine a cake is cut into 3 slices, one third would be one of those slices. This means that we have 3 thirds in any whole n...

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Answered by Rachel B. Maths tutor
44835 Views

Differentiate y=(x^2+5)^7

In this example instead of multiplying out 7 brackets it is useful to use the chain rule, which is used to differentiate the composition of more than one function. If we let what is inside the bracket equ...

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Answered by Rachel B. Maths tutor
6639 Views

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