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6x2 + 4x - 10 = 06x2 + 10x - 6x - 10 = 02x(3x + 5) - 2(3x + 5) = 0(2x - 2)(3x + 5) = 0Case 1: 2x - 2 = 02x = 2x = 1Case 2: 3x +...
Evaluate each bracket first. We have:(2a + a)x(5a - a) = (3a)x(4a)Then, multiply both brackets.(3a)x(4a) = 12a2
(6(x+4) + x(x-3) )/ ((x-3)(x+4)) = 1 obtain a common denominator and write as one fraction. (6x+24+x2-3x ) /( x2-3x+4x-12) = 1 multiply out the brackets. (x2+3x+24)/ (xJRAnswered by Jana R. • Maths tutor2508 Views
We see a product of two things, so we should consider integration by parts (IBP). IBP is usually useful when either 1) you can differentiate or integrate one of the two things repeatedly to eventually get...
There are two possible solutions, substitution and using absolute value. Here, we will use absolute value method.By definition of square root we get: sqrt(x^2) = |x|. By definition of absolute value we ge...
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