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Given 6x+2y=4 and 5x+y=8, solve the simultaneous equations to find x and y.

The key here is to eliminate one of the variables; it doesn't matter whether we start by trying to get rid of x or y we will arrive at the same solution. For us to eliminate either x or y it is easiest to...

RM
Answered by Rebecca M. Maths tutor
8462 Views

Given y=(1+x^3)^0.5, find dy/dx.

In order to solve this question, we need to use the chain rule when differentiating. The chain rule formula is dy/dx= (dy/du)(du/dx). Let u=1+x3Differentiating with respect to x gives du/dx...

RM
Answered by Rebecca M. Maths tutor
6143 Views

Solve the Simultaneous Equations -3X + 4Y=11 & X-2Y = -5 to find the values of X and Y

Simultaneous Equations are equations involving 2 or more unknowns that have the same value in each equation. The aim is to eliminate all but one unknown. This will then allow us to find the value of th...

EU
Answered by Emehakon U. Maths tutor
13623 Views

A price is decreased by 27% The new price is £1138.80 Work out the original price.

This can be solved by making an equation for the old price.

Make the old price be equal to x.

To find the new price the old price must be multiplied by the percentage of the...

OG
Answered by Oliver G. Maths tutor
4665 Views

N = 2a + b. a is a 2 digit square number, b is a 2 digit cube number. What is the smallest possible value of N?

First, the smallest values of a and b must be found and then substituted into the equation for N.

To find a.

A square number is a number that is the result of multiplying an...

OG
Answered by Oliver G. Maths tutor
3708 Views

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