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A curve has equation y = 4x + 1/(x^2) find dy/dx.

As in every case dy/dx can be found by differentiating each term individually with respect to x.

Let's first tackle the 4x term.

As always the ...

CH
Answered by Callum H. Maths tutor
10228 Views

Solve x^2 + 8x +3 = 0 by completing the square.

Using the completing the square method:

1. Notice (x+4)2 = x2 + 8x +16 which differs from the question by a constant

TD
Answered by Tutor21349 D. Maths tutor
22590 Views

Integrate 4x^3 + 6x^2 +4x + 3

Each term is integrated according to the formula:

axb --> (a/(b+1))x(b+1)

A constant k integrates to kx 

Since this is indefinite inte...

EH
Answered by Emma H. Maths tutor
5514 Views

Differentiate y = 2x^3 + 6x^2 + 4x + 3 with respect to x.

Each term is differentiated according to the formula:

y = axb --> dy/dx = b*ax(b-1)

Constants differentiate to zero.

Therefore in this...

EH
Answered by Emma H. Maths tutor
7479 Views

Find the gradient of a curve whose parametric equations are x=t^2/2+1 and y=t/4-1 when t=2

Remember that the gradient of a curve is expressed as dy/dx. This can be solved by using the chain rule:

dy/dx = dy/dt*dt/dx. The dt in the denominator of the first term, and the numerato...

AS
Answered by Abigail S. Maths tutor
9089 Views

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