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In order to add or subtract terms to/from each other, both of their denominators (the number on the bottom of the fraction) must be the same. In this case they are different, so the first step is to try a...

2x²+6x-3=0To begin, we need to make sure x² is by itself, meaning that we divide the whole equation by 2. So from here we get (2x²+6x-3=0) / 2 = x²+3x-3/2=0. No...

(x+3)(x+2)=F=xx= x^2O=x2=2xI=3x=3xL= 3*2=6=x^2 + 2x + 3x + 6= x^2 + 5x + 6

3x+2y=8 (1)2x+5y=-2 (2)So you need to have a common multiple of either x or y in this example I’ll equate the x of both equations so I’ll multiply (1) by 2 and (2) by 3 2( 3x+2y=8). 6x+4y=16 (3).3(2x+5y=-...

x= (3 + ln(11))/4