Top answers

Maths
All levels

Solve the following simultaneous equations to give a value for both x and y: 3x+3y=9 and 2x+3y=5

  1. Subtract the bottom equation from the top equation to get 3x-2x=9-5 (you don't see no y values in this equation as the y's have disappeared and cancelled eachother out as 3y-3y=0)2) So 3x-2x=9-5 equ...
AF
Answered by Amy F. Maths tutor
3101 Views

simplify fully: (3x^2 - 8x -3)/(2x^2 -6x)

First of all, to simplify this fraction, we need to factorise the top and bottom equations. We shall start with the top equation. Now looking at the equation: 3x2 - 8x -3, we know that it's a q...

AH
Answered by Amanda H. Maths tutor
3925 Views

Prove that the product of 3 consecutive integers is divisible by 6

If you set the three consecutive integers to be n, n+1 and n+2, we know that one of the numbers must be divisible by 2 and one must be divisible by 3. For example if you had your three numbers as: 5, 6, 7...

SK
Answered by Shreeya K. Maths tutor
14004 Views

A Block of mass 2kg is on an a smooth inclined plane where sin@ = 3/5 at point A. Point B is 5 meters down the incline. Find the time it will take for the block to reach point given it is at rest at point A.

So to start with draw a free body diagram of a block on the slope at point A with the forces acting on it which will be the downward force of mass x g (2g) due to gravity and the reaction force 2gcos@. Th...

HS
Answered by Harry S. Maths tutor
2923 Views

Why is the definite integral between negative limits of a function with positive values negative even though the area bound by the x-axis is positive? for example the integral of y=x^2 between x=-2 and x=-1

Referring back to the definition of an integral, it is the sum of small elements on the x-axis (dx) multiplied by the value of the function at that point (y) commonly expressed as the sum of ydx. Since x ...

Answered by Maths tutor
3040 Views

We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences