Why is the definite integral between negative limits of a function with positive values negative even though the area bound by the x-axis is positive? for example the integral of y=x^2 between x=-2 and x=-1

Referring back to the definition of an integral, it is the sum of small elements on the x-axis (dx) multiplied by the value of the function at that point (y) commonly expressed as the sum of ydx. Since x is negative in this region, so is dx, resulting in all of the elements of the sum being negative. A useful way of remembering this is to think about the problem graphically, and what quadrant our function crosses:x,y > 0 Both ydx (and in turn the integral in this quadrant) is positivex > 0 > y Both ydx (and in turn the integral in this quadrant) is negativex < 0 < y Both ydx (and in turn the integral in this quadrant) is negativex,y < 0 Both ydx (and in turn the integral in this quadrant) is positive
(which is case 3 for the function y=x2 for negative limits)

Related Maths A Level answers

All answers ▸

How do I integrate ln(x)?


The curve C is defined by x^3 – (4x^2 )y = 2y^3 – 3x – 2. Find the value of dy/dx at the point (3, 1).


How do I find the integral ∫(ln(x))^2dx ?


Using logarithms solve 8^(2x+1) = 24 (to 3dp)


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy