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find the integral of y=x^2 +sin^2(x) with respect to x between the limits 0 and pi

intergal₀^pi(x^2 + sin^2(x))dx = integral₀^pi(x^2 + 1/2 - cos(2x)/2)dx since sin^2(x) + cos^2(x) = 1cos^2(x) - sin^2(x) = cos(2x)2sin^2(x) = 1 - cos(2x)thereforei...

Answered by • Maths tutor

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How would you simplify this: ((4x+1)/4)+((1-3x)/3)

You must manipulate the fractions so that they both have the same denominator. To do this, multiply the first fraction by 3 and the second by 4 so that they both have the denominator 12. The problem can t...

Answered by Isobel H. • Maths tutor

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BIDMAS

When solving a maths problem you can't just do it in any order. 'BIDMAS' is a way to remember what order to solve in. It stands for: BracketsIndicesDivisionMultiplicationA

Answered by Anna H. • Maths tutor

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If the two shorter lengths of the triangle have sizes 4cm and 3cm, what is the length of the longest side?

5 cm

Answered by Diana S. • Maths tutor

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Integrate xsin(x) with respect to x

For this use integration by parts, letting the integral = T. Let u = x and dv/dx = sin(x). Differentiating u with respect to x gives du/dx = 1. Integrating dv/dx with respect to x gives v = - cos(x). Now,...

Answered by Ethan M. • Maths tutor

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