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How do you differentiate using the chain rule?

The chain rule is used where the equation you are looking to differentiate is a function that is itself raised to a power. For example, we might have y = (x²-2)³ and want to differen...

Answered by Oliver B. • Maths tutor

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Derive the following: f(x)=(96/x^2)+kx

f'(x)=(-192/x^3)+k

Answered by Adrien D. • Maths tutor

1690 Views

A family go into a shop, they buy three sandwiches and two packets of crisps. It costs them £9. Another family buy five sandwiches and six packets of crisps. It costs them £19. How much does two sandwiches and five packets of crisps cost?

We will call sandwiches S and packets of crisps C. These are the 'unknowns'. From the information we can write down two equations. Equation 1: 3S + 2C = 9 and Equation 2: 5S + 6C = 19. We need two equatio...

Answered by Nicholas W. • Maths tutor

2896 Views

Line A is parallel to the line 4y+12x=24. Find the equation of Line A if it passes through the point (5,40/3).

Line A and line 4y+12x+24 are parallel. This means that they have the same gradient. In y=mx+c the gradient of the line is m. We can rearrange the equation 4y+12x+24 to find m. To begin with subtract 12x...

Answered by Chloe B. • Maths tutor

2855 Views

C and D are two events such that P(C) = 0.2, P(D) = 0.6 and P(C|D) = 0.3. Find P(D|C), P(C’ ∩ D’) & P(C’ ∩ D)

Here we use the formula for conditional probability:P(C|D)xP(D)=(𝑃(C∩D))= 0.3x0.6=0.18Note: 𝑃(C∩D)=𝑃(D∩C)=0.18Hence P(D|C)=𝑃(D∩C)/P(C) = 0.18/0.2 = 0.9P(C'∩D') = P(C'|D')xP(D')P(C'|D) = 0.7P(D')=0.4P(C')=...

Answered by Sunny V. • Maths tutor

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